-3x^2-13x+44=0

Solution for -3x^2-13x+44=0 equation:

-3x^2-13x+44=0

a = -3; b = -13; c = +44;
Δ = b2-4ac
Δ = -132-4·(-3)·44
Δ = 697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{697}}{2*-3}=\frac{13-\sqrt{697}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{697}}{2*-3}=\frac{13+\sqrt{697}}{-6}
$